A math problem.

My friend told me to solve this, and I know there are a bunch of math experts on here, so yeah.
It goes a little something like this ...
If you subtract 3 from me, square the result, divide by 5 and then subtract 4 times me, the result is 11 minus me

Sub x for 'me':[(x-3)^2]/5 - 4 x = 11 - xAnswer is 23 or -2 once you work it out algebraically and get a quadratic equation.EDIT: Here is your quadratic equation:(x^2)/5 - 21/5 x - 46/5 = 0

make sure you understand the question before taking consideration to it...

Replying to #3

So is that. I understand the question, I just can't be bothered with it :3
Thanks Hypr!

Hypr · #2Sub x for 'me':[(x-3)^2]/5 - 4 x = 11 - xAnswer is 23 or -2 once you work it out algebraically and get a quadratic equation.EDIT: Here is your quadratic equation:(x^2)/5 - 21/5 x - 46/5 = 0

Thats what i was going to say...:)

Hypr · #2[(x-3)^2]/5 - 4 x = 11 - x

Weren't you supposed to square the result of x-3 not take the power of 2 of it? Logically to remove the square root call you'd have to take the power of 2 on the other side of the equation mark.

Replying to #6

Uh...huh? How is (x-3)^2 not squaring the result of x-3?

i hate math!

Replying to #8

I hate spam!
thanks for the help Hypr, that'll show him :D

tehuber1337 · #7Uh...huh? How is (x-3)^2 not squaring the result of x-3?

Well to me squaring = the square root, which is the opposite of the power of. But then again, I usually do maths in Danish, so it's very possible that it's just a term I'm not familiar with.

"^" = used in common scientific calculators of now, "powers of 2..."
" " = I can't find the symbol for the radical(used for acquiring the square root)EDIT: Found it:

Seph · #10Well to me squaring = the square root, which is the opposite of the power of. But then again, I usually do maths in Danish, so it's very possible that it's just a term I'm not familiar with.

Ah, I see. In my experience, squaring has always been taking the power of two.

yeah squaring is taking the power of two by the way whats your education level?

To whom is that question directed?

To all member...i think

a*a = squaring a
sqrt(a) = square root of aAnd math doesn't suck. It simplifies.

sure sure, that what they all say

x-3=[[x^2]/5]-4x=11-xshift to one side you get, [x^2]-30x-70=0you can't factor in the result because you could get a multiple of 70 but you can't get a total of 30. this means the quadratic equation, which will result in a mixed number.i got [30+-sqrt[620]]/2

maybe i should let you guys toutor me, cause i suck at math and super smart at physics...... damn im weird i know

a man once proved 2=1 at the youtube
but the truth is he's an idiot:1. Let a and b be equal non-zero quantities
a = b \,2. Multiply through by a
a^2 = ab \,3. Subtract b^2 \,
a^2 - b^2 = ab - b^2 \,4. Factor both sides (a - b)(a + b) = b(a - b) \,5. Divide out (a - b) \,
a + b = b \,6. Observing that a = b
b + b = b \,7. Combine like terms on the left
2b = b \,8. Divide by the non-zero b
2 = 1 \,at the highlighted equation, the man actually divided both side by 0(a-b)