math problem i need help

how would one solve
root(x-27) + root(x) = 9so solve for x
and show steps

It would help if you were telling us what kind of math problem it is :/
Are you trying to expand, is it Linear equations, what?

just solve for x
what number does x have to be to make the equation equal to zero
Post Merge: [time]1252814348[/time]
i mean 9 not zero

So you're square rooting them?
As in like v/---- when it's written?If so, x = 36 :D

What is this, I don't even.

Sorry, I lost x at the fair yesterday. He ran away. :(

Cloudboii, your posts are not helping him at all...zzzzzzzzzzz, here's the worked-out solution. Hopefully this helps you learn more about algebraic manipulation tricks.SolutionEDIT (Sept. 21, 2009): Fixed link so that everyone can see it.

Why not, my posts gave the answer :/You just showed an extended way of doing it, I gave him the straight out answer.

Replying to #8

He was asking for steps to solve the problem. Giving just the answer only doesn't do much help to anyone.

zzzzzzzzzz · #1how would one solve
root(x-27) + root(x) = 9so solve for x
and show steps

Replying to #9

Fwiw, √ is useful in this.

Oh, sorry >.<
Jumped into the question xD

root(x-27) + root(x) = 9
root(x-27) + root(x) = 9 // ^2
(x-27)^2 + x^2 = 81
x^2-729 + x^2 = 81
x^2 + X^2 = 81 + 729
2x^2 = 810
2x^2 = 810 // /2
x^2 = 405
x^2 = 405 // root
x = 20.124...
x ~ 20I'm not sure if it's right. =P I need to check it with paper.

Replying to #12

Should be (√(x-26) - √x)^2.Hypr's already provided a thorough answer, anyway.

Replying to #13

Damn, I knew I failed. XD
But it was fun to do some math problems for a long time. =P

Here are the steps. The trick is to move the sqrt(x) to the right, square both sides, then the x term will cancel on both sides, leaving you with just sqrt(x) and a constant.

sqrt(x-27) + sqrt(x) = 9
sqrt(x-27) = 9 - sqrt(x)
sqrt(x-27)^2 = (9 - sqrt(x))^2
x-27 = 81 - 18*sqrt(x) + sqrt(x)^2
x-27 = 81 - 18*sqrt(x) + x
-27 = 81 - 18*sqrt(x)
-108 = -18*sqrt(x)
6 = sqrt(x)
36 = x

Edit: NekoHennuli, line 3: (a+b)^2 is not the same as a^2 + b^2.

I worked it out and got X = 27.

Subbing x = 27 into the original equation gives 0 + 5.19... = 9, which is clearly incorrect.At any rate, Hypr's already solved this (showing working as required), so this thread doesn't really have a purpose anymore.

It still does. I just supplied the steps to the solution (which apparently nobody figured out or were bothered enough to post...).

Replying to #18

Hypr · #7Cloudboii, your posts are not helping him at all...zzzzzzzzzzz, here's the worked-out solution. Hopefully this helps you learn more about algebraic manipulation tricks.Solution

Admittedly, the steps differ slightly, but oh well.

Awww, people shouldn't post non-bold Solution links... I can hardly notice them...